Question

find range of function
$f(x) = - \sqrt{3 - 2x - {x}^{2} }$
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Answer 1

Answer:

$f(x) = - \sqrt{3 - 2x - {x}^{2} } \\ = - \sqrt{ - {x}^{2} - 2x + 3 } \\ = - \sqrt{ - ( {x}^{2} + 2x - 3)} \\ = - \sqrt{ - ( {x}^{2} + 3x - x - 3} ) \\ = - \sqrt{ - (x(x + 3) - 1(x + 3))} \\ - \sqrt{ - (x - 1)(x + 3)}$