Question

find range of the ball on the incline​

Answer 1

Answer:

75m

Explanation:

Components of initial velocity

$${ u }_{ x }=u\cos { \left( \theta +\alpha  \right)  } $$

$${ u }_{ y }=u\sin { \left( \theta +\alpha  \right)  } $$

Components of acceleration

$${ a }_{ x }=g\sin { \alpha  } ;{ a }_{ y }=-g\cos { \alpha  } $$

Time of flight$$T=\cfrac { 2u\sin { \left( \theta +\alpha  \right)  }  }{ g\cos { \alpha  }  } $$

∴ Range of flight$$=R=\cfrac { { u }^{ 2 } }{ g\cos { \alpha  }  } \left\{ \sin { \left( 2\theta +\alpha  \right)  } +\sin { \alpha  }  \right\} $$

$$u=20 \dfrac{m}{s},\theta =37°,\alpha =\left( 90-37 \right) °=53°,g=10㎨$$

∴ We get R=75m