find range of this function
Attachments:
Answers
Answered by
0
Domain and range both are equal
Attachments:
Answered by
0
Answer:
Step-by-step explanation:
y=x/1+x^2
y+yx^2=x
yx^2-x+y=0
x=1+root (1-4y^2) / 2y
range of y. = domain of x
so 1-4y^2 > or equal to 0
R-[-1/2,1/2]
Similar questions