Math, asked by roushan136, 1 year ago

find range of this function​

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Answers

Answered by RashidUmRani
0

Domain and range both are equal

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Answered by nagathegenius
0

Answer:

Step-by-step explanation:

y=x/1+x^2

y+yx^2=x

yx^2-x+y=0

x=1+root (1-4y^2) / 2y

range of y. = domain of x

so 1-4y^2 > or equal to 0

R-[-1/2,1/2]

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