Question

Find rate of effusion of a mixture of He and SO2, (in mol ratio 1:1) relative to CH4 at same total pressure & temperature through same size hole.​

Answer 1

Explanation:

HEY MATE ........

The relative rate of effusion is inversely proportional to the square root of molar mass.It is directly proportional to the number of moles .The molar masses of sulphur dioxide and methane are 64 g/mol and 16 g/mol respectively.

$under \: similar \: condition \: of \: pressure \: and \: temperature \: \\ \\ \frac{rso2}{rch4} = \frac{ \sqrt{mch4} }{mso2} = \frac{ \sqrt{16} }{64} = \frac{1}{2}$

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