Question

find Rate of Interest of P=9600 , T=3 months ,S.I =72​

Answer 1

Answer:

$\huge \bf \: given$

• Principal = ₹9600
• Time = 3 months
• Simple interest = ₹72

$\huge \bf \: to \: find$

Rate

$\huge \bf \: answer$

$rate \: = \frac{i }{p \: \times t}$

As we know that rate is calculated in per annum so we have to convert time into year.

3 months = 0.25 years

$r \: = \frac{72}{9600 \times 0.25}$

$r \: = 33.33333$