Question

find rate when compound anually p=40000 a=48400 time=2years ​

Answer 1

Answer:

$rate \: = > 10\%$

Step-by-step explanation:

$Given: \\ Principal (P) = Rs. 40000, \\ Amount (A) = Rs. 48400 \: \: and \\ Time ( n) = 2years \\ ∵ \: \: A= P(1 + \frac{r}{100} ) {}^{n} \\ Rs. 48400 = Rs. 40000( 1+ \frac{r}{100} ) {}^{2} \\ = > \frac{48400}{40000} = (1 + \frac{r}{100} ) {}^{2} \\ = > \frac{484}{400} = (1 + \frac{r}{100} ) {}^{2} \\ = >( \frac{22 }{20 } ) {}^{2} = (1 + \frac{r}{100} ) {}^{2} \\ = > \frac{22}{20} = 1 + \frac{r}{100} \\ On \: further \: simplification, \: we \\ get: \: \: r= 10\%$

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