Find ratio in which a line 2x-3y-9=0 divide line segment (2,3),(3,5)
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So, let's use the Two point formula to find the equation of second line. According to the formula,
x- x1/x2-x1= y-y1/y2-y1
LetA(x1,y1) and B(x2,y2)
x-1/2–1= y- 3/7–3
x-1/1= y-3/4
4x-4= y-3
So, 4x-y= 1
This is the equation of second line. Now, we have to solve them simultaneously to find the coordinates of point of intersection. By solving it , as we solve the linear equation in two variable, we get the coordinates as C(10/7, 33/7).Let the ratio be m:n
By using the formula for internal division,
X=mx2-nx1 /m+n
10/7= 2m-n/ m+n
10(m+n)= 7(2m-n)
10m+10n= 14m-7n
10n+7n= 14m-10m
17n= 4m
m/n=17/4
So, the ratio is 17:4.
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