Question

find reading of spring balance​

Answer 1

Answer:

Here,we can think from non inertial frame of reference that as the lift is moving upward with an acceleration of g10,so net force acting downward for the two blocks will be their weight+(g/10)their mass.



So,if the tension in the string is T,we can write for the larger block as, 3g+3g10−T=3a (as it is going down)

similarly for the smaller block T−1.5g−1.5g10=1.5a (where, a is the acceleration of the blocks relative to the lift)

Solving both we get, T=(115)g

Now,the spring is attached to the pulley which is bearing the tension of the string from both the side,so the spring will show a reading of 2T=(225)g=43.12N

so,reading of the spring balance will be 22g5g=4.4Kg