Question

find real numbers x and y such that 3x+2iy-ix+5y=7+5i

Answer 1

Answer:

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(3x−7)+2iy=−5y+(5+x)i

For two complex numbers to be equation

Real parts of true numbers should be equal Imaginary parts should also be equal

3x−7=−5y

2y=5+x=7y=2(5+x)

3x−7=x−5(5+x)

6x−14=−25−5x=7x=−11

∴x=−1,y=(25+x)=25−1=2

Answer 2

Answer:

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Step-by-step explanation:

I DONT NOW