Question

find reduction , oxidation , oxidising agent and reducing agent (1) S + 4HNO3 = SO2 + 4NO2 +2H2O . ....​

Answer 1

Answer:

Reducing agent:S

Oxidising agent :HNO3

Explanation:

S (s) + 4 HNO3 (aq) → 4 NO2 (l) + SO2 (aq) + 2 H2O (l)

This is an oxidation-reduction (redox) reaction:

S0 - 4 e- → SIV

(oxidation)

4 NV + 4 e- → 4 NIV

(reduction)

S is a reducing agent, HNO3 is an oxidizing agent.