Question

find relation between x and y such that (x,y) is eqvidistant from points (7,1) (3,5)​

Answer 1

Let P(x,y) be equidistant from the points A(7,1) and B(3,5).

AP=BP

AP  

2

=BP  

2

 

(x−7)  

2

+(y−1)  

2

=(x−3)  

2

+(y−5)  

2

 

x  

2

−14x+49+y  

2

−2y+1=x  

2

−6x+9+y  

2

−10y+25

x−y=2