Question

Find relationship between sum and zeros of 4u²+8u​

Answer 1

Let f(u)=4u2+8u

To calculate the zeros of the given equation, put f(u)=0.

4u2+8u=0

4u(u+2)=0

u=0,u=−2

The zeros of the given equation is 0 and −2.

Sum of the zeros is 0+(−2)=−2.

Product of the zeros is 0×−2=0.

According to the given equation,

The sum of the zeros is,

a−b=4−(8)

=−2

The product of the zeros is,

ac=40

=0