Question

Find remainder
192 X 37X1953X1956/19​

Answer 1

Answer:

Let the quotient obtained in both the cases be n.

X = 237 n + 192

Y = 117 n + 108

Adding both the equations,

X + Y = 354 n + 300

= 118 ( 3 n ) + 118 ( 2 ) + 64

=118 ( 3 n + 2 ) + 64.

Therefore, the remainder obtained when sum of X & Y is divided by 118 is 64.