Math, asked by suhassurdkar2411, 4 months ago

find remainder
(21x^4-14x^2+7x)÷7x^3

Answers

Answered by hegde5

2

Step-by-step explanation:

(21x⁴-14x²+7x)÷7x³

=21x⁴-14x²+7x

7x³

=7x³+3x-14x²+7x

7x³

=7x³*3x + -14x²+7x

7x² 7x³

=3x+ - 14x²+7x

7x²

so quotient →3x reamainder →-14x²+7x.

Answered by tennetiraj86

0

Answer:

0 is the remainder for the given problem

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