Question

find remainder of x^3+3x^2+3x+1 by x-1/2​

Answer 1

3 is the remainder. hope this will help.

Answer 2

Remainder = $\frac{27}{8}$

Step-by-step explanation:

Given,

Dividend = x³ + 3x² + 3x + 1

Divisor = x - $\frac{1}{2}$

If divisor = 0

x - $\frac{1}{2}$ = 0

2x - 1 = 0

2x = 1

x = $\frac{1}{2}$

Substituting the value of x in the dividend:

x³ + 3x² + 3x + 1

($\frac{1}{2}$)³ + 3($\frac{1}{2}$)² + 3($\frac{1}{2}$) + 1

($\frac{1}{8}$) + 3 × ($\frac{1}{4}$) + 3 × ($\frac{1}{2}$) + 1

$\frac{1}{8}$ + $\frac{3}{4}$ + $\frac{3}{2}$ + 1

L.C.M. of 8, 4, and 2 is 8

$\frac{(1*1) + (3 * 2) + (3*4) + (1*8)}{8}$

$\frac{1+6+12+8}{8}$

$\frac{27}{8}$

∴ remainder = $\frac{27}{8}$

Learn more:

Factorise the following

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