find remainder using remainder therom
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Answer:
Step-by-step explanation:
X^3 +1
Put x= - 1
= (- 1)^3 +1
= - 1 +1
=0
Hence it is a root of the polynomial
harshita6967:
it is right
Answered by
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p(x)= (x3+1)
g(x)= (x+1)
now,g(x)= x+1
x+1= 0
x= (-1)
now, p(x) becomes,
= (-1×-1×-1 +1)
= 0
So, the remainder is 0
IF U FIND IT HELPFUL, THE PLZ MARK ME BRAINLIEST
g(x)= (x+1)
now,g(x)= x+1
x+1= 0
x= (-1)
now, p(x) becomes,
= (-1×-1×-1 +1)
= 0
So, the remainder is 0
IF U FIND IT HELPFUL, THE PLZ MARK ME BRAINLIEST
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