Question

find remainder when 3p4-4p3-3p-1 is divided by p-1​

Answer 1

Answer:

Pic attached .. check that out

Answer 2

☯GIVEN :

• $\bf{a(p) =3p^4 - 4p^3-3p-1}$

• $\bf{b(p) = p-1}$

☯TO FIND :

• Remainder.

➲SOLUTION :

• By Remainder Theorem :

Let us assume b(p) = 0.

$: \longrightarrow{ \tt{p-1= 0}}$

$: \longrightarrow{ \tt{p = 0 +1}}$

$: \longrightarrow{ \bf{p = 1}}$

✞Substituting the value of p :

$:\longrightarrow{\tt{a(p) =3p^4 - 4p^3-3p-1}}$

$: \longrightarrow{\tt{a(1) =3(1)^4-4(1)^3-3 \times 1-1}}$

$: \longrightarrow{\tt{a(1) =3 \times 1-4\times 1 - 3\times 1-1}}$

$: \longrightarrow{\tt{a(1) = 3-4 - 3-1}}$

$\longrightarrow{\tt{a(1) =3- 8 }}$

$\dashrightarrow{\underline{ \purple{\boxed{\bf{a( 1) = - 5}}}}}$

$\huge{\red{\therefore}}$ Remainder = -5.