Question

Find remainder when 3x3-6x2+3x-7/9is divided by 3x-4

Answer 1

Answer:

-3/9

Step-by-step explanation:

3x-4=0

x=4/3

p(x)=3x^3-6x^2+3x-7/9

p(4/3)=3×(4/3)^3-6×(4/3)^2+3×(4/3)-7/9

=3×64/27-6×16/9+3×4/3-7/9

=64/9-32/3+4-7/9

=64/9-96/9+36/9-7/9

=(64-96+36-7) /9

=(100-103) /9

= -3/9