Math, asked by raj1103, 1 year ago

find remainder when 41^77 is divided by 7

Answers

Answered by Ghosh1
6
41 divided by 7 remainder is 6

41^2 divided by 7 remainder is 1

41^3 divided by 7 remainder is 6

41^4 divided by 7 remainder 1

if exponent is odd remainder is 6

if exponent is even reminder is 1

in the given case exponent is odd,so remainder is 6

Answered by mridulas10308
1

Answer:

answer is

7 - 1 = 6

Step-by-step explanation:

when 41 divided by 7 answer is -1 by putting mod

so it is 7-1 = 6

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