Question

find remainder when 9x^3-3x^2+x-5 is divided by x-2/3

Answer 1

$put \: x = \frac{2}{3} \\ remainder = 9 {( \frac{2}{3} )}^{3} - 3 {( \frac{2}{3}) }^{2} + \frac{2}{3} - 5 \\ = \frac{9 \times 8}{27} - \frac{3 \times 4}{9} + \frac{2}{3} - 5 \\ = \frac{8}{3} - \frac{4}{3} + \frac{2}{3} - 5 \\ = \frac{8 - 4 + 2 - 15}{3} \\ = \frac{ - 9}{3} \\ = - 3$

Answer 2

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