Find remainder when f (x) =x^3-6x^2 + 2x-4 is divided by 9 (x)= 1-2x
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Answered by
0
C
−
8
35
The zero of g(x)=1−2x is x=
2
1
Now, by remainder theorem the remainder should be f(
2
1
)
∴f(
2
1
)=(
2
1
)
3
−6(
2
1
)
2
+2(
2
1
)−4
=(
8
1
)−6(
4
1
)+1−4
=(
8
1
)−(
4
6
)−3
=
8
1−12−24
=−
8
35
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