Find remainder when P(x) = 2x^3+ bx^2+7x 12 is divided by x + 1
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Answer:
Given:P(X)=2x³+bx²+7x+12
G(X)=X+1
By long division method:
Step-by-step explanation:
x+1✓2x³+bx²+7x+12→2x² +(b-2)x+(9-b)
_2x³+_2x²
→(b-2)x²+7x+12
_ (b-2)x²+_(b-2)x
→(9-b)X+12
→_(9-b)x+_9-b
→12-9+b
Therefore r(X)=12-9+b
=3+b
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