Question

Find remainder when p(x)=x^4+2x^3-3x^2+x-1 is divided by g(x)=x-2

Answer 1

using remainder theorem
x-2=0
x=2
putting x=2
g(x)=16+16-12+1
=21
so remainder=21

Answer 2

Here is your answer.....
x-2=0
x=2
p(x)=x^4+2x^3-3x^2+x-1
p(2)=2^4+2*2^3-3*2^2+2-1
=16+16-12+1
=21 Ans

Hope it helps.....