Question

Find remainder when p (X) = xcube - 6x square + 2x - 4, is divided by 3x - 1

Answer 1

Answer:

here is your answer mate...

Step-by-step explanation:

when we divide f(X) by g(X)

g(X) = 3x-1

so root = 1/3

then by remainder theorem

f(1/3) = (1/3)^3-6*(1/3)^2+2*1/3-4

= 1/27-6/9+2/3-4

= 1/27-4

= 1-27*4/27

= -107/27

hope it helps u...

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