Question

Find remainder when p(y)=
${y}^{3} + {y}^{2} + 2y + 3 \div y + 2$
​

Answer 1

Remainder would be: -5

Step-by-step explanation:

refer to the attachment

Hope it helps!

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Answer 2

Answer:

use remainder theorem then, y+2 =0

y=0-2 = -2

Put p (-2) = (-2)^3 +(-2)^2 + 2 (-2) +3

= -8 +4 -4 +3

= -8 +0+3

= -8 +3

= -5 ans.

Hopes it helps you