Question

find remainder when P(y) = y^3 + y² + 2y +3
Is divided
by (y+2) without actual
division ?​

Answer 1

Answer: By remainder theorom

Zero of y+2 is -2

Remainder=p(-2)=

(-2)^3+(-2)^2+2(-2)+3=

-8+4-4+3=-5

Step-by-step explanation:

Answer 2

Step-by-step explanation:

Given, p(y)=y³+y²+2y+3

Zero of (y+2)⇒y+2=0⇒y= -2

Now, we know remainder theorem states that if p(y) is divided by any linear polynomial (y-a) then the remainder is p(a). So if we apply this to the question,

∴p(-2)=(-2)³+(-2)²+2(-2)+3

          = -8+4-4+3

          = -5

∴Remainder of p(y)= -5

Hope it helps you!!  :)