find remainder when x^3+3X^2+3X+1 divided by x+pie
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Answer:
π³+3π²
−3π+1
Step-by-step explanation:
x+π = 0
⇒ x= (-π)
p(x)=x³
+3x²+3x+1
Replace x by −π, we get
p(−π)=(−π)³ +3(−π)²+3(−π)+1
⇒p(−π)=(−π³)+3(π²) −3π+1
⇒p(−π)=−π³+3π²
−3π+1 [ Can't simplify any further. Don't take the value of π as it is not mentioned]
Hope it is helpful. Take care.
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