find remainder when x^3-3x^2+4x-12 divided by x-3
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Question:-
- Find the remainder when x³ - 3x² + 4x - 12 is divided by x - 3.
Answer: -
- Dividing x³ - 3x² + 4x - 12 by x - 3,
- Dividend: x³ - 3x² + 4x - 12
- Divisor : x - 3
Now,
- Put divisor as 0,
- x - 3 = 0
- .°. x = 3
Now,
- Let p (x) = x³ - 3x² + 4x - 12
Putting value of x,
- p(3) = (3)³ - 3(3)² + 4(3) - 12
- = 27 - 27 + 12 - 12
- = 0 + 0
- = 0
Thus, remainder = p(3) = 0
So, the remainder when x³ - 3x² + 4x - 12 is divided by x - 3 is 0.
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