Question

find remainder when x^3-3x^2+4x-12 divided by x-3
plz give answer​

Answer 1

Answer:

Step-by-step explanation:

ANSWER:-

By Using Remainder Theorem:-

x-3=0

x = 3_____________(1)

Now placing the value of x in given equation,

$x^{3}-3x^{2}+4x-12$

$=(3)^{3}-3(3)^{2}+4(3)-12$

$= 27 - 27 +12-12$

$= 0$ is the required remainder.

REMAINDER THEOREM:-

In this , we substitute the value of x with respect to what is given as divisor given in question.

SOME OTHER METHODS:-

DIVISION ALGORITHM:

dividend = divisor * quotient + remainder

LONG DIVISION METHOD

Manually dividing dividend and divisor.

Answer 2

Question: Find the remainder when x³ - 3x² + 4x - 12 is divided by x - 3.

Answer:

Dividing x³ - 3x² + 4x - 12 by x - 3,

Dividend: x³ - 3x² + 4x - 12

Divisor : x - 3

Now, Put divisor as 0,

x - 3 = 0

.°. x = 3

Now,

Let p (x) = x³ - 3x² + 4x - 12

Putting value of x,

p(3) = (3)³ - 3(3)² + 4(3) - 12

= 27 - 27 + 12 - 12

= 0 + 0

= 0

Thus, remainder = p(3) = 0

So, the remainder when x³ - 3x² + 4x - 12 is divided by x - 3 is 0.