FIND REMAINDER WHEN X POWER 4+4X POWER 3-6X+7 IS DIVIDED BY X-3
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Let f(x)=x
4
+4x
3
−5x
2
−6x+7.
Let R be the remainder obtained when f(x) is divided by x+3.
Equate x+3 to 0 and put the value of x in f(x).
x+3=0
⟹x=−3
R=(−3)
4
+4(−3)
3
−5(−3)
2
−6(−3)+7
=81−108−45+18+7
=−47
Thus required remainder is −47
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