find remainder when x³-3x²+3x-1 is divided byx-1/2
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Answer:
p(x) = x^3 - 3x^2 + 3x -1
p(1/2) = (1/2)^3 - 3×(1/2)^2 + 3×1/2 -1
= 1/8 - 3/4 +3/2 -1
= 1/8 -(3×2/4×2) + (3×4/2×4) -1
= 1/8 - 6/8 + 12/8 - 8/8
=1-6+12-8/8
=-1/8
therefore,
The reminder is -1/8
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