Question

find remainder when x³-bx²+5-2b is divided by x-b​

Answer 1

Answer:

5-2b

Step-by-step explanation:

By the Remainder Theorem, let the divisor be equal to 0 i.e x - b = 0. Hence x=b

Let us put x=b

$p(x) = {x}^{3} - b {x}^{2} + 5 - 2b \\ p(b) = {b}^{3} - b( {b}^{2} ) + 5 - 2b = 5 - 2b$

p(x) is the dividend. x-b is the divisor. p(b) is the remainder.

Hence,

Remainder = 5-2b