Question

find remainder when xpower4 -ypower4 is divided by x-y

Answer 1

Hi Friend !!!

Here is ur answer !!!

x^4 - y ^4 = (x-y) (x+y) (x²+y²)

x^4-y^4 / x-y = (x+y)(x²+y²)


Hope it helps u :-)

Answer 2

Hiii. .....friend

The answer is here,

$= > \: {x}^{4} - {y}^{4} \: divided \: by \: x - y$

$= > \: \frac{ {x}^{4} - {y}^{4} }{x - y}$

$= \frac{ (x - y)(x + y)( {x}^{2} + {y}^{2} )}{x - y}$

$= > \: (x + y)( {x}^{2} + {y}^{2} )$
x-y divides x^4 -y^4 exactly. Hence,

The remainder is 0.

:-)Hope it helps u.