Question

Find remaining angles in each of the following triangles​

Answer 1

Answer:

70

Step-by-step explanation:

pq =qr(given)

angle p is equal to angle r (because angles opposite to equal sides of a triangle are equal.)

angle p+ angle r +angle q is 180(angle sum property of a triangle.)

x+x+40=180

2x=140

x=70

angle p and angle r are 70

Answer 2

Answer:

70° & 70°

Step-by-step explanation:

In ΔPQR,

PQ≅QR ...(Given)

∴ ∠QPR ≅∠QRP ...( Isosceles triangle theorem )

Let, ∠QPR=∠QRP= x

In ΔPQR,

∠PQR+∠QPR+∠QRP=180° ...( Sum of all angles of a triangle is 180°)

40°+x+x=180°

40+2x=180

2x=180-40

2x=140

x=70

∴In ΔPQR, ∠QPR=∠QRP=70°