Question

find reminder if x raze to power 2017+1 is divisible by x+1

Answer 1

$\bold{\boxed{HEY!!!}}$



HERE IS YOUR ANSWER :-



$( {x}^{2017} + 1) \div( x + 1) \\ \\ \\ \: let \: p(x) = {x}^{2017} + 1 \\ \\ \\ by \: the \: remainder \: theorem \: \\ \\ \\ p( - 1) \: will \: be \: the \: remainder \\ \\ \\ p( - 1) = {( - 1)}^{2017} + 1 \\ \\ \\ = - 1 + 1 \\ \\ \\ = 0 \\ \\ \\ so \: 0 \: is \: the \: remainder \:$