Question

find resistance in the circuit? please answer​

Answer 1

Answer:

The effective resistance of the circuit is 40 Ω.

Explanation:

Two 20 Ω resistors are in parallel connection. So their effective resistance can be calculated as:

1/R₁ = 1/R + 1/R

1/R₁ = 1/20 + 1/20 = 2/20

1/R₁ = 1/10

∴ R₁ = 10 Ω

Two 10 Ω resistors are also connected in a parallel manner. Their effective resistance is:

1/R₂ = 1/R + 1/R

1/R₂ = 1/10 + 1/10 = 2/10

1/R₂ = 1/5

∴ R₂ = 5 Ω

We have R₃ = 15 Ω and R₄ = 10 Ω

Now all the remaining resistances are connected in a series pattern and the effective resistance can be calculated using the equation:

R = R₁ + R₂+ R₃+ R₄

R = 10 + 5 + 15 + 10

R = 40 Ω