find resistance of the following
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The two 1Ω resistances are in parallel. So, equivalent resistance is
1+1
1×1
Ω=
2
1
Ω
Similarly, the two 2Ω resistances are in parallel. So equivalent resistance is
2+2
2×2
Ω=1Ω
Now these 1Ωand
2
1
Ω resistances are in series with the two 3Ω resistances.
So the equivalent resistance of the circuit is (1+
2
1
+3+3)Ω
R=
2
15
Ω
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