Question

find resistance?????Plzzzz help me........ ​

Answer 1

In the given circuit , we are given two resistors of resistances 6 Ω and 30 Ω , which are connected in series and a battery of 9 Volts .

(a) .

When resistors are connected in series , Eq. resistance will be found by adding the individual resistances

➠  $\sf{\orange{R_{eq}=R_1+R_2}}\ \; \bigstar$

Let , R₁ = 6 Ω & R₂ = 30 Ω

So , Eq. resistance = 6 Ω + 30 Ω

➤ Eq. resistance = 36 Ω  $\pink{\bigstar}$

(b) .

Ohm's law states that , Potential difference in the circuit is directly proportional to the current passing in the circuit  

➳ V = I Rₑ₉

➳ I = 9 / 36

➳ I = 1 / 4

➳ I = 0.25 A  $\green{\bigstar}$

(c) .

Potential difference across R₁ :-

V = IR₁

V = (0.25) (6)

V = 1.5 V  $\red{\bigstar}$

Potential difference across R₂ :-

⭆ V = IR₂

⭆ V = (0.25)(30)

⭆ V = 7.5 V  $\purple{\bigstar}$

Answer 2

$formula \: \: of \: \: resistance \: \\ \\ v = \frac{r}{t} \\ \\ v = \frac{9}{36} = \frac{3}{12} = \frac{1}{4} = 0.25 \\ \\ so \: \: the \: \: resistance \: \: \\ will \: \: be \: \: 0.25$