find resistance???Plzzzz help me out.....
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16
Observe attachment for entire scenario , ( After have been modified )
10 Ω , 2.5 Ω are connected in parallel ,
Let it be R₁ ,
Now ,
R₁ , 10 Ω are connected in series ,
Let it be R₂ ,
Now ,
R₂ , 12 Ω are connected in parallel ,
Let it be R₃ ,
Now ,
R₃ , 10 Ω are connected in series ,
Let it be R₄ ,
R₄ , 16 Ω are connected in parallel ,
Let it be R₅ ,
So , Equivalent resistance b/w A and B in the given circuit is 8 Ω .
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Answered by
20
Answer:
Between A and B
let the resistance 10 Ω ,2.5 they are in parallel
RP = 2 Ω
RP is in series with above 10 Ω
RP = 10+2
= 12 Ω
Then 12 Ω are in resistance = 6 Ω
Then 6 Ω and above 10 Ω are in series 16 Ω
Therefore RP = 1/10 + 1/16
= 8 Ω
Between A and B = 8 Ω
hope this helps you
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