Question

find resistence between a and b​

Answer 1

According to the figure: [ In the attachment ]

Case-1:

Resistors b and c are connected in series.

Case-2:

case-1 and resistor d are connected in parallel.

Case-3:

case-2, resistors a and e all are connected in series.

Now,

${\orange{ \boxed{ \boxed{ \begin{array}{cc} \sf \: case - 1 : \\ \\ R_{bc} = b + c = 5 + 5 = 10 \: ohm \\ \\ \sf \: case - 2 : \\ \\ \frac{1}{R_{bcd}} = \frac{1}{R_{bc}} + \frac{1}{d} = \frac{1}{10} + \frac{1}{5} = \frac{3}{10} \\ \\ \therefore \: R_{bcd} = \frac{10}{3} \: ohm \\ \\ \sf \: case - 3 : \\ \\ R_{eq} =a + R_{bcd} + e \\ \\ = 5 + \frac{10}{3} + 5 \\ \\ = \frac{40}{3} \: ohm \\ \\ \\ \therefore \: \rm \: equivalent \: resistance \: R_{eq} = \frac{40}{3} \:ohm \end{array}}}}}$