find rhe difference between compound interest and simple intrest of sum rs 12000 at thr rate of 12% p.a for 2 years
Answers
Step-by-step explanation:
Principal (P) = Rs 12000
Rate of Interest (R) = 12% per annum
Time (T) = 2 years
To be found :-
The difference between Compound Interest (C.I) ans Simple Interest (S.I)
Simple Interest (S.I) = \bf \frac{P \times R \times T}{100}
Simple Interest (S.I) = \bf \frac{12000 \times 12 \times 2}{100}
Simple Interest (S.I) = \bf 2880
∴ Simple Interest (S.I) = Rs 2880
Now,
Compound Interest (C.I) = \bf P[ (1+\frac{R}{100})^T-1]
Compound Interest (C.I) = \bf 12000[ (1+\frac{12}{100})^2-1]
Compound Interest (C.I) = \bf 12000[ (1+\frac{3}{25})^2-1]
as\: \frac{12}{4}=3 \:and\: \frac{100}{4}=25
Compound Interest (C.I) = \bf 12000[(\frac{25+3}{25})^2-1]
Compound Interest (C.I) = \bf 12000[(\frac{28}{25})^2-1]
Compound Interest (C.I) = \bf 12000[\frac{784}{625}-1]
Compound Interest (C.I) = \bf 12000[\frac{784-625}{625}]
Compound Interest (C.I) = \bf 12000\times \frac{159}{625}
Compound Interest (C.I) = \bf 3052.8
∴ Compound Interest (C.I) = Rs 3052.8
So,
Difference between (C.I) ans (S.I) is
= Rs 3052.8 - Rs 2880
= Rs 172.8
Answer:
Rs.172.8
Step-by-step explanation:
Principal Amount- Rs.12000
Rate of Interest-12%
Time-2 years
1.) Maturity Amount = Princiapal Amount(1+rate/100)^t ime
MA= 12000(1+12/100)^2
MA= 12000(112/100)^2
MA= 12000(28/25)^2
MA= 12000*784/625
MA= Rs.15052.8
Interest earned CI = 15052.8-12000 = Rs.3052.8
2.) Simple interest= principal*rate*time/100
SI= 12000*12*2/100
Interest earned SI= Rs.2880
3.) Difference-) CI-SI
= 3052.8-2880
=Rs.172.8
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