Question

Find rhe equation of the circle which has centre at (3,4) and touches the straight line 5x+12y=1.​

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

ANSWER

Perpendicular distance of the centre from the line will be equal to the radius as the line is tangent to the circle

∴d=

13

5(3)+12(4)−1

=r

d=r=

13

62

So, the equation of circle will be

(x−3)

2

+(y−4)

2

=(

13

62

)

2

x

2

+y

2

−6x−8y+

169

381

=0