Question

find rhe zeroes if the polynomial x^3-5x^2+6x.without drawing graph​

Answer 1

Heya!!

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Explanation:

We have to factor $x^{3} - 5x^{2} + 6x = 0$ completely.

Begin by factoring out $x$ common to each term, we have

$x.(x^{2} -5x +6) = 0$

Now, using middle term splitting method, we get

$x.(x^{2} -2x-3x +6) = 0$

$x.(x-2).(x-3) =0$

Therefore, the zeroes of the polynomial are 0, 2 & 3.

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