Question

Find rms voltage drop across elements

Answer 1

Explanation:

Series RLC Circuit

Firstly, let us define what we already know about series RLC circuits.

Series RLC Circuit at Resonance

Since the current flowing through a series resonance circuit is the product of voltage divided by impedance, at resonance the impedance, Z is at its minimum value, ( =R ). Therefore, the circuit current at this frequency will be at its maximum value of V/R as shown below.

Series Circuit Current at Resonance

The frequency response curve of a series resonance circuit shows that the magnitude of the current is a function of frequency and plotting this onto a graph shows us that the response starts at near to zero, reaches maximum value at the resonance frequency when IMAX = IR and then drops again to nearly zero as ƒ becomes infinite. The result of this is that the magnitudes of the voltages across the inductor, L and the capacitor, C can become many times larger than the supply voltage, even at resonance but as they are equal and at opposition they cancel each other out.

Circuit Current at Resonance, Im

I = V/R

Inductive Reactance at Resonance, XL

XL = 2πfL

Voltages across the inductor and the capacitor, VL, VC

VL = VC ( At resonance)

VL = I x XL

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