find ROOT 2 ROOT 3 ROOT 5
Anonymous:
Root 30
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for 2
by phytagoras tho.
h sq =b sq + p sq
so
h sq = 1 sq +1 sq
=2
so h= root 2
for root 3
similar process
but p = root 2
b=1
for root 5
similar process
but p=root 4
b=1
by phytagoras tho.
h sq =b sq + p sq
so
h sq = 1 sq +1 sq
=2
so h= root 2
for root 3
similar process
but p = root 2
b=1
for root 5
similar process
but p=root 4
b=1
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