Question

find root by completing square method. 4x^2 + 3x + 5 = 0​

Answer 1

this is answer of your question

Answer 2

Answer:-

Given:

${4x}^{2} + 3x + 5 = 0$

${x}^{2} + \frac{3}{4} x + \frac{5}{4} = 0$

${x}^{2} + \frac{3}{4} x + ( \frac{3}{4} )^{2}$

$= \frac{ - 5}{4} + ( \frac{3}{8} ) ^{2}$

$(x + \frac{3}{8} ) ^{2} = \frac{ - 5}{4} + \frac{9}{64}$

$(x + \frac{3}{8} ) ^{2} = \frac{ - 71}{64} < 0$

But,

$(x + \frac{3}{8} ) ^{2}$

☀︎Cannot be negative for any real value of x. So,there is no real value of x satisfying the given equation. Therefore, the given equation has no real roots.☀︎