Question

Find root of 10.5 geometrically

Answer 1

Draw a line AB of10.5 units Extend the line making BC = 1unit, and AC = 11.5 units Take the midpoint of AC as M = 11.5/2 = 5.75 Draw a semi-circle from A to C as M as the centre. Draw a line perpendicular to AC at point C until is intersects and bisects with the semicircle forming a new point called D CD=√10.5 Put your compass needle at point M and then the other end at point D. Draw an arc till it reaches the number line or intersects with the number line and the point formed let's call it D2(or any other thing you like) D=D2=√10.5
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