Question

find root of 6x^2-x-7=0 by factorisation​

Answer 1

Answer:

hope it will help u please thanks for it..

Answer 2

Answer:

-1,7/6

Step-by-step explanation:

6x^2-x-7

the middle term (-x) can be written as (6x-7x)

6x^2+6x-7x-7=0

6x(x+1)-7(x+1)=0

(6x-7)(x+1)=0

if, 6x-7=0             if,x+1=0

   6x=7                    x= -1

   x=7/6

therefore,roots of the equation are -1,7/6