Question

find root of the equation z^6+64=0 where z is complex nmbr

Answer 1

z^6+64=0
z is complex number
value of i^2 in complex = -1
so. z^6-(i^2*2^2)^3=0
z^6-(2i) ^6=0
z^6=(2i) ^6
now ans is z=2i