find root of (x-7)²-16=0
Answers
Answered by
2
(X-7)^2=16
(X-7)=+-(4)
X=7+-(4)
X=7+4. X=7-4
X=11 X=3
(X-7)=+-(4)
X=7+-(4)
X=7+4. X=7-4
X=11 X=3
Answered by
16
Answer:
(x - 7)² - 16 = 0
(x - 7)² - (4)² = 0
[(x - 7) - 4][(x- 7) + 4] = 0
(x - 7 - 4)(x - 7 + 4) = 0
(x - 11)(x - 3) = 0
So, x - 11 = 0 and x - 3 = 0
⇒ Roots are 11 and 3.
Step-by-step explanation:
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